Basically,
Ohms law is used to calculate a resistor value in order to convert the 0-20ma signal to a voltage.

**Current to Voltage Conversion Circuit Diagram**

####
**Example (0-20 mA to 0-10 VDC)**

**R = V/I**where

**V**is the Voltage,

**I**is the current and R is the resistance

**R**= 10V/0.020A =

__500 Ohms__

**0-20 mA to 0-10 VDC**Conversion Circuit Diagram
V = I*R = 0*500 = 0V

V = I*R = 0.020*500 = 10V

####
**Example (4-20 mA to 2-10 VDC)**

**R = V/I**where

**V**is the Voltage,

**I**is the current and R is the resistance

**R**= 10V/0.020A =

__500 Ohms__

**4-20 mA to 2-10 VDC**Conversion Circuit Diagram
V = I*R = 0.004*500 = 2V

V = I*R = 0.020*500 = 10V

####
**Example (0-20 mA to 0-5 VDC)**

**R = V/I**where

**V**is the Voltage,

**I**is the current and R is the resistance

**R**= 5V/0.020A =

__250 Ohms__

**0-20 mA to 0-5 VDC**Conversion Circuit DiagramV = I*R = 0*250 = 0V

V = I*R = 0.020*250 = 5V

#### Convert 0-10 VDC to 0-20 mA Using Resistor

####
**Note:-**

**To avoid damage you must ensure that the external current source has short-circuit protection in all conductor cases.**

The external resistor is a source of error because of its dependency on
temperature and its inaccuracy.

In order to obtain measuring results that are as precise as possible it is
recommended to use resistors with tolerances that are as small as possible.

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